14x-49-x^2=0

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Solution for 14x-49-x^2=0 equation: 



14x-49-x^2=0

We add all the numbers together, and all the variables

-1x^2+14x-49=0

a = -1; b = 14; c = -49;
Δ = b2-4ac
Δ = 142-4·(-1)·(-49)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-14}{-2}=+7$

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